Re: [xsl] Dynamic DTD declaration in output

In XSLT 2.0 you can do:

<xsl:template match="/">
  <xsl:result-document doctype-system="{$DefaultDTDPath}" method="xml" 
encoding="utf-8">
    ....
  </xsl:result-document>
</xsl:template>

Michael Kay
Saxonica

> On 15 May 2019, at 06:45, Trevor Nicholls 
> trevor(_at_)castingthevoid(_dot_)com 
> <xsl-list-service(_at_)lists(_dot_)mulberrytech(_dot_)com> wrote:
>
> Hi
>  
> I've got a simple stylesheet which is executed as a pre-process when XML 
> documents are loaded into FrameMaker. At the moment the stylesheet includes 
> the line
>  
>     <xsl:output doctype-system="/path/to/docs.dtd" method="xml" 
> encoding="UTF-8" />
>  
> Because this stylesheet will be used by different users in several different 
> contexts, it would be brilliant if the path to the DTD could be 
> parameterised. I know the following is invalid but the purpose of this post 
> is to ask if there is any way of engineering an equivalent:
>  
>     <xsl:param name="DefaultDTDPath" />
>     <xsl:output doctype-system="{$DefaultDTDPath}" method="xml" 
> encoding="UTF-8" />
>  
> XSL version has to be 1.0 or 2.0.
>  
> Thanks
> T
>  
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