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Re: [xsl] Each value in an XPath array is a sequence of elements ... how to access a particular element in a particular array value?

2019-06-06 09:47:18
$first_group is an array of nodes. To turn it into a sequence of nodes, use 
"?*". So it's


(parentheses because I don't have the operator precedences in my head)

Michael Kay

On 6 Jun 2019, at 15:26, Costello, Roger L. costello(_at_)mitre(_dot_)org 
<xsl-list-service(_at_)lists(_dot_)mulberrytech(_dot_)com> wrote:

Hi Folks,

This is an extension to a question that I had last week ...

Recall that I want to group the <row> elements in the following XML. Each 
group should consist of those <row> elements that have the same ARPT__IDENT, 
TRM__IDENT values.


That XML consists of two groups. Each group has two <row> elements.

Martin provided a great XPath 3.1 expression for doing the grouping:

<xsl:variable name="groups" as="array(element(row))*" select="
   let $keys := 
       distinct-values($rows/concat(ARPT__IDENT, '|', TRM__IDENT))
       for $i in $keys
           array {$rows[$i = concat(ARPT__IDENT, '|', TRM__IDENT)] }          

In the following, I select the first group:

<xsl:variable name="first-group" select="$groups[1]" />

Next, I want to select the <row> element in the first group that has Foo as 
the value of the <Data> element. I thought that this would be the appropriate 
XPath expression:

<xsl:variable name="Foo-row-first-group" select="$first-group/row[Data eq 

Apparently it is not the appropriate XPath expression, because I get this 
error message:

      Axis step child::element(Q{}row) cannot
      be used here: the context item is not a node

What is the appropriate XPath expression, please?


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