Hi All,
I have a situation where I want to split a short paragraph into sentences
and use them in different parts of my output. I am using
<xsl:analyze-string> because I want to account for a sentence ending with a
. or ?. This will work except if there are any children of the paragaph,
like the <emphasis> in the second sentence. Can I split a paragraph into
sentences and still keep the markup?
Here is my input document:
<?xml version="1.0" encoding="UTF-8"?>
<root>
<p>This has one sentence? Actually, it has <emphasis>two</emphasis>. No,
it has three.</p>
</root>
My stylesheet:
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:xs="http://www.w3.org/2001/XMLSchema"
xmlns:rq="http://www.frameexpert.com"
exclude-result-prefixes="xs rq"
version="2.0">
<xsl:output indent="yes"/>
<xsl:strip-space elements="root"/>
<xsl:template match="/root">
<xsl:copy>
<xsl:apply-templates/>
</xsl:copy>
</xsl:template>
<xsl:template match="p">
<xsl:variable name="sentences"
select="rq:splitParagraphIntoSentences(.)"/>
<p><xsl:value-of select="$sentences[1]"/></p>
<note>Something in between.</note>
<p><xsl:value-of select="$sentences[position()>1]"/></p>
</xsl:template>
<xsl:function name="rq:splitParagraphIntoSentences">
<xsl:param name="paragraph"/>
<xsl:analyze-string select="$paragraph" regex=".+?[\.\?](\s+|$)">
<xsl:matching-substring>
<sentence><xsl:value-of
select="replace(.,'\s+$','')"/></sentence>
</xsl:matching-substring>
</xsl:analyze-string>
</xsl:function>
</xsl:stylesheet>
My output:
<?xml version="1.0" encoding="UTF-8"?>
<root>
<p>This has one sentence?</p>
<note>Something in between.</note>
<p>Actually, it has two. No, it has three.</p>
</root>
What I want is this:
<?xml version="1.0" encoding="UTF-8"?>
<root>
<p>This has one sentence? </p>
<note>Something in between.</note>
<p>Actually, it has <emphasis>two</emphasis>. No, it has three. </p>
</root>
Any suggestions will be appreciated.
Rick
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