[xsl] How to read an XML file that is in a subfolder or sub-subfolder or

Hi Folks,

My XSLT program has a variable $filename which contains the name of an XML 
file. The XML file is in a folder named "files" or one of its subfolders or one 
of its sub-subfolders or one of its sub-sub-subfolders or ...

In other words, it's somewhere in the tree of folders rooted at "files."

I want to open the XML file (wherever it's located within "files") and read it 
into an XSLT variable. Is there a way to do this?

/Roger
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