Hello everone,
I started to play with XSLT 3 accumulators and am not sure I
understand the specifications correctly with regards to the order of
accumulator rules.
Take the following example:
<xsl:transform version="3.0"
xmlns:xs="http://www.w3.org/2001/XMLSchema";
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
<xsl:output method="text"/>
<xsl:mode on-no-match="shallow-skip" use-accumulators="#all"/>
<xsl:accumulator name="accumulator" as="xs:integer" initial-value="0">
<xsl:accumulator-rule match="element">
<xsl:sequence select="1"/>
</xsl:accumulator-rule>
<xsl:accumulator-rule match="element">
<xsl:sequence select="2"/>
</xsl:accumulator-rule>
</xsl:accumulator>
<xsl:template match="/">
<xsl:apply-templates/>
<xsl:sequence select="accumulator-after('accumulator')"/>
</xsl:template>
</xsl:transform>
And apply it to the following document:
<element/>
From my reading of the specs I would expect value of the accumulator
to be 2 because both rules match the element node and the rule
selecting 2 is last in document order. But this stylesheet returns 1
when I run it with Saxon EE 10.1.
This seems to be a bug in Saxon, doesn't it?
Best,
-- David
--
David Maus M.A.
Www: http://dmaus.name
Twitter: @_dmaus
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