Hi Folks,
[This is a summary of yesterday's discussion, for the archives.]
I have an XML document that consists of <row> elements:
<Document>
<row>
<x>1</x>
<y>2</y>
</row>
<row>
<x>3</x>
<y>4</y>
</row>
<row>
<x>1</x>
<y>2</y>
</row>
</Document>
I want to eliminate duplicate rows. row[1] and row[3] have the same elements
with the same values. They are duplicates. I only want one of them.
Michael Kay responded:
In this situation, you can use grouping:
<xsl:for-each-group select="row" group-by="x, y" composite="yes">
<xsl:sequence select="current-group()[1]"/>
</xsl:for-each>
Roger: Wow! That simple for-loop is doing an enormous amount of work – grouping
elements by their content, iterating over the groups, selecting the first of
each group (thus, deleting the duplicates). That is beautiful code. Thank you
Michael.
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