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[xsl] All combinations from a sequence

2021-09-30 09:20:12
Good afternoon,

I have a sequence of items and I need all combinations (not permutations) in 
all possible lengths.

I saw what I want described as "powerset" in the Python docs: powerset([1,2,3]) 
--> () (1,) (2,) (3,) (1,2) (1,3) (2,3) (1,2,3)

In XPath notation and based on strings:

my:powerset(('A','B','C','D'))

This sequence of 4 items should result in a sequence of 16 strings (order not 
important) representing all possible combinations: 'ABCD', 'ABC', 'ABD', 'ACD', 
'AB', 'AC', 'AD', 'A', 'BCD', 'BC', 'BD', 'B', 'CD', 'C', 'D', ''

Or more general, the result could be an array of sequences.

To get this as a solution in XSLT/XPath I am currently fiddling around with a 
recursive function including head() and tail() and count() but I have the 
impression I am overcomplicating things.

I am wondering, if this is a use case for fold-left() or if I should rather 
think of a filter that drops 0, 1, 2 or 3 items from the sequence. Or is there 
a well-known algorithm with a cool name?

Any hints are, as always, very welcome, thanks a lot,

- Michael
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