Hi Prady,
Assuming you meant "string split by ;" I came up with this template doing the
work:
<xsl:template match="Ip">
<xsl:variable name="entries" select="tokenize(text(), '\s*;\s*')"
as="xs:string*"/>
<xsl:element name="nums" namespace="http://xmlns.ieee.org/V2">
<xsl:value-of select="($entries ! substring-before(., '#')) =>
string-join(';')" />
</xsl:element>
</xsl:template>
It uses XSLT 3 features, because they are so great, and – frankly – I am not
motivated to do this using XSLT1. This will most probably involve a recursive
template using substring-before and substring-after.
- Michael
Am 13.10.2021 um 17:32 schrieb Prady Prady
prady(_dot_)chin(_at_)gmail(_dot_)com
<xsl-list-service(_at_)lists(_dot_)mulberrytech(_dot_)com>:
Team,
Can somebody help me to replace string that is in between # and ; with blank.
I need to include this is oracle bpel which only supports xslt 1.0
From:
<IpsCollection xmlns="http://xmlns.oracle.com/aa
<http://xmlns.oracle.com/aa>">
<Ips>
<Ip>q1#11.11.11.111;q2#22.22.22.22</Ip>
</Ips>
</IpsCollection>
To:
<v2:Ops xmlns:v2="http://xmlns.ieee.org/V2 <http://xmlns.ieee.org/V2>">
<v2:nums>q1;q2</v2:nums>
</v2:Ops>
Thank you very much for your help!
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