You might consider
$nodes | ()
a bit more intuitive.
Michael Kay
Saxonica
On 28 Dec 2021, at 19:23, Eliot Kimber
eliot(_dot_)kimber(_at_)servicenow(_dot_)com
<xsl-list-service(_at_)lists(_dot_)mulberrytech(_dot_)com> wrote:
Hmph.
That is certainly much more efficient 😊 but is not necessarily obvious (at
least not to me).
Thanks!
E.
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From: Martin Honnen martin(_dot_)honnen(_at_)gmx(_dot_)de
<mailto:martin(_dot_)honnen(_at_)gmx(_dot_)de>
<xsl-list-service(_at_)lists(_dot_)mulberrytech(_dot_)com
<mailto:xsl-list-service(_at_)lists(_dot_)mulberrytech(_dot_)com>>
Date: Tuesday, December 28, 2021 at 1:15 PM
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
<mailto:xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com>
<xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
<mailto:xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com>>
Subject: Re: [xsl] XQuery/XPath 3.1: Node List to Node Set ("distinct nodes")
[External Email]
On 28.12.2021 20:10, Eliot Kimber
eliot(_dot_)kimber(_at_)servicenow(_dot_)com
<mailto:eliot(_dot_)kimber(_at_)servicenow(_dot_)com> wrote:
I couldn’t find an answer in my google and markmail searching so I
thought I’d ask here:
Given an arbitrary list of nodes that may contain duplicates, what is
the most efficient way to reduce the node list to a set?
The solution I came up with is a recursive function:
(:
Get the unique nodes from the supplied sequence
@param nodes The sequence of nodes to evaluate
@return A sequence of nodes such that each node in $nodes exists exactly
once.
:)
declare function dutils:distinctNodes($nodes as node()*) as node()* {
dutils:_getDistinctNodes($nodes, ())
};
declare function dutils:_getDistinctNodes($nodes as node()*, $resultList
as node()*) as node()* {
if (exists($nodes))
then
let $node := head($nodes)
return dutils:_getDistinctNodes(tail($nodes), ($resultList | $node))
else $resultList
};
Which works but I feel like I’m missing some obvious way to do this more
directly, but I’m not seeing it.
Am I missing a better solution?
$nodes/.
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