Actually, that's not equivalent. My solution (using string()) treats an
empty transition element and an absent transition element as equivalent;
DImitre's solution treats them as distinct.
This is clearly what Roger (the OP) wanted. He wrote:
I want a count of the number of distinct transition values, where row
elements with no transition element are counted as 1.
On Fri, May 27, 2022 at 9:05 AM Michael Kay mike(_at_)saxonica(_dot_)com <
xsl-list-service(_at_)lists(_dot_)mulberrytech(_dot_)com> wrote:
Use count(distinct-values(/test/row/string(transition)))
I would use the more obvious and self-explanatory:
let $test := /test/row
return
count(distinct-values($test/transition)) + 1[$test[not(transition)]]
Actually, that's not equivalent. My solution (using string()) treats an
empty transition element and an absent transition element as equivalent;
DImitre's solution treats them as distinct.
Michael Kay
Saxonica
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Cheers,
Dimitre Novatchev
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Truly great madness cannot be achieved without significant intelligence.
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To avoid situations in which you might make mistakes may be the
biggest mistake of all
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Quality means doing it right when no one is looking.
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You've achieved success in your field when you don't know whether what
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Sanity is madness put to good use.
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