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RE: TCP Checksum Interoperability

2002-04-08 07:30:33
FYI, The 'offending' stacks are PC/TCP (reception) and in Open VMS
(transmission).

This is an age-old issue; the following dates from 1985(!):

http://www-mice.cs.ucl.ac.uk/multimedia/misc/tcp_ip/8502.mm.www/0389.html

I think RFC 1624 is missing the UDP case, where +0 means "not calculated".
Indeed, RFC 768 asserts that the two values (+0 and -0) are equivalent.

Part of the problem is that there isn't an RFC standard that deals with the
issue of a zero checksum, apart from for UDP.

The protocol RFCs don't specify the details and the implementation RFCs
(1071, 1141, 1624) state explicitly that they are not standards, "It is not
a standard, but a set of useful implementation techniques".

They are a very good idea but not mandatory.

That's why I said I thought the receiver wasn't compliant: it rejects -0 as
invalid.

Chris

-----Original Message-----
From: Lloyd Wood [mailto:l(_dot_)wood(_at_)eim(_dot_)surrey(_dot_)ac(_dot_)uk]
Sent: 05 April 2002 21:45
To: Michael Smith
Cc: 'CTrobridge(_at_)baltimore(_dot_)com'; 'sra+ietf(_at_)hactrn(_dot_)net'; 
'ietf(_at_)IETF(_dot_)ORG';
'tcp-impl(_at_)grc(_dot_)nasa(_dot_)gov'
Subject: RE: TCP Checksum Interoperability


On Fri, 5 Apr 2002, Michael Smith wrote:

The last time this came up for a TCP implementation I used to
maintain, our interpretation of Robustness Principle applied to this
problem dictated that we shouldn't send segments with 
checksum fields
set to all ones (that is, we shouldn't send ~(+0)), but 
that we had to
accept either ~(+0) or ~(-0) in received segments.

Strictly speaking, either zero state is completely legal

Not so. Please read RFC1624 sections 3-5.

L.

<L(_dot_)Wood(_at_)surrey(_dot_)ac(_dot_)uk>PGP<http://www.ee.surrey.ac.uk/Personal/L.Wood/>




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