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Re: equivalent for backreference \1

2002-08-03 10:20:51
  On Aug 03 at 12:08, Allan Wind spoke:

On 2002-08-03 16:56:29, Hanspeter Roth wrote:
I realy would like every character out of [-!-,:-(_at_)](_dot_)

Fair enough, just seemed like if your set of chars was small, it would
be worth a shot even if ugly :-)

I have now a solution using the $MATCH variable:

*   ^Subject: .*\/[-!-,:-(_at_)]
* $ ^Subject: .*$MATCH.?.?$MATCH.?.?$MATCH

Thanks anyway.

-Hanspeter
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