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Re: Node selection based on parent attribute

2002-08-30 06:59:29
If I use:
<xsl:template match="tree">
 <xsl:apply-templates select="menu"/>
</xsl:template>

<xsl:template match="menu">
  <xsl:for-each select="menu[(_at_)id=$id]/menu">
        <xsl:value-of select="@id"/>
   </xsl:for-each>
</xsl:template>


with an xml structure of :

<tree>
 <menu id="1" countryID="1" description="Com site" href="">
<menu id="4" countryID="1" description="My Buisness Type" href=""></menu>
     <menu id="5" countryID="1" description="Home Office" href=""></menu>
<menu id="15" countryID="1" description="Small buisness" href=""></menu>
 </menu>
</tree>

passing through a parameter of 1 using:
<xsl:param name="id" select="menu"/>

Then it doesn't bring back anything, can you see anthing wrong with the above.

Cheers,


From: ronald heller <ronald(_at_)salience(_dot_)nl>
Reply-To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: Re: [xsl] Node selection based on parent attribute
Date: Fri, 30 Aug 2002 14:45:37 +0200


<menu id=6>
        <menu id=7/>
        <menu id=8/>
</menu>

<xsl:for-each "menu[(_at_)id=$id]/menu">
<xsl:value-of select="@id"/>
</xsl:for-each>

this would get you 7 & 8 as a result if $if would be 6.

cheers
RH
At 12:32 PM 30-08-02 +0000, you wrote:

Hi,
I would like to produce a list of child nodes from a parent that has a specific attribute value, ie with the following xml structure I want to just retrive the children of the menu node with an id of 6.
<menu id=6>
<menu id=7/>
<menu id=8/>
</menu>
<menu id=9>
<menu id=10/>
<menu id=11/>
</menu>

I have tried
<xsl:for-each "../@id=$id">
<xsl:value-of select="@id"/>
</xsl:for-each>
Using a param passed in from asp.
Am I on the right track, and would the above method be the best to retrieve a certain section of a heirachacal xml structure based on a parent attribute.
I am using asp with the msxml parser.
Thanks in advance.





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