If I use:
<xsl:template match="tree">
<xsl:apply-templates select="menu"/>
</xsl:template>
<xsl:template match="menu">
<xsl:for-each select="menu[(_at_)id=$id]/menu">
<xsl:value-of select="@id"/>
</xsl:for-each>
</xsl:template>
with an xml structure of :
<tree>
<menu id="1" countryID="1" description="Com site" href="">
<menu id="4" countryID="1" description="My Buisness Type"
href=""></menu>
<menu id="5" countryID="1" description="Home Office" href=""></menu>
<menu id="15" countryID="1" description="Small buisness"
href=""></menu>
</menu>
</tree>
passing through a parameter of 1 using:
<xsl:param name="id" select="menu"/>
Then it doesn't bring back anything, can you see anthing wrong with the
above.
Cheers,
From: ronald heller <ronald(_at_)salience(_dot_)nl>
Reply-To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: Re: [xsl] Node selection based on parent attribute
Date: Fri, 30 Aug 2002 14:45:37 +0200
<menu id=6>
<menu id=7/>
<menu id=8/>
</menu>
<xsl:for-each "menu[(_at_)id=$id]/menu">
<xsl:value-of select="@id"/>
</xsl:for-each>
this would get you 7 & 8 as a result if $if would be 6.
cheers
RH
At 12:32 PM 30-08-02 +0000, you wrote:
Hi,
I would like to produce a list of child nodes from a parent that has a
specific attribute value, ie with the following xml structure I want to
just retrive the children of the menu node with an id of 6.
<menu id=6>
<menu id=7/>
<menu id=8/>
</menu>
<menu id=9>
<menu id=10/>
<menu id=11/>
</menu>
I have tried
<xsl:for-each "../@id=$id">
<xsl:value-of select="@id"/>
</xsl:for-each>
Using a param passed in from asp.
Am I on the right track, and would the above method be the best to
retrieve a certain section of a heirachacal xml structure based on a
parent attribute.
I am using asp with the msxml parser.
Thanks in advance.
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