Here Demitre uses the function count(ancestor::*|.) three times within
the same template - can anyone tell me if this gets re-evaluated each
time, therefore using a variable would be better, or if it gets stored
(as some kind of optimisation maybe), so using a variable is unecessary?
cheers
andrew
-----Original Message-----
From: Dimitre Novatchev [mailto:dnovatchev(_at_)yahoo(_dot_)com]
Sent: 27 September 2002 11:46
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] Re: getting all nodes from a certain level in the xml
hierarchy
--- "Peter Menzel" <mai00bfy at studserv dot uni-leipzig dot
de> wrote:
Hallo
my problem is the following:
my XML document maps the structure of a folder tree (just like the
unix
file
hierarchy) but without files, e.g.:
<Folder NAME="/">
<Folder NAME="a"/>
<Folder NAME="b">
<Folder NAME="ba"/>
<Folder NAME="bb"/>
</Folder>
...
<Folder NAME="z">
<Folder NAME="za">
...
<Folder NAME="very deep folder"/>
...
</Folder>
</Folder
</Folder>
The real folder NAMEs are like real folder names, and have no
specific
length or content.
The depth of the deepest node is unknown.
I need to access all nodes that have the same depth.
So first i need root, then all direct childs of root, then all nodes
that
are two levels under root, because i want tu put them in a table
like:
level | 0 | 1 | 2 ... x
------+--+----+----- ---------------
| / | a | ba very deep folder
| | b | bb
...
| | z | za
first I started to try <xsl:for-each select="//Folder"> and then
<xsl:for-each select="//Folder/Folder"> but because I do
not know the
depth
of the tree, this won't work..
Can anybody help me, what is the direction i should go?
I don't think there is an easy way to use XPath for adressing nodes
on
the
same level?
Nice greetings, Peter
Here's a simple solution using the Muenchian method for grouping:
source xml (provided by you):
----------------------------
<Folder NAME="/">
<Folder NAME="a"/>
<Folder NAME="b">
<Folder NAME="ba"/>
<Folder NAME="bb"/>
</Folder>
<Folder NAME="z">
<Folder NAME="za">
<Folder NAME="very deep folder"/>
</Folder>
</Folder>
</Folder>
stylesheet:
----------
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="text"/>
<xsl:key name="kDepth" match="Folder"
use="count(ancestor::*)" />
<xsl:template match="/">
<xsl:for-each select="//Folder
[
generate-id()
=
generate-id(key('kDepth',
count(ancestor::*)
)[1]
)
]">
<xsl:value-of select="concat('Level ',
count(ancestor::*),
': '
)"/>
<xsl:for-each select="key('kDepth',count(ancestor::*))">
<xsl:value-of select="concat(@NAME, '; ')"/>
</xsl:for-each>
<xsl:text>
</xsl:text>
</xsl:for-each>
</xsl:template>
</xsl:stylesheet>
Result:
------
Level 0: /;
Level 1: a; b; z;
Level 2: ba; bb; za;
Level 3: very deep folder;
Hope this helped.
=====
Cheers,
Dimitre Novatchev.
http://fxsl.sourceforge.net/ -- the home of FXSL
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