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Re: Selecting a random node from source-tree

2002-09-26 08:11:43
"Martin Lormes" <martin dot lormes at gmx dot net> wrote:

In XSLT 1.0

How do I select a random node from the source-tree or from an
external
document?
I was thinking of an XPath expression like this:

document('funnies.xml')/funnies/quote[random()]

Can I avoid using extension elements?

Yes, use the "randNext" template from FXSL.

More information is contained in the article: 

"Casting the Dice with FXSL: Random Number Generation Functions in
XSLT"

http://fxsl.sourceforge.net/articles/Random/Casting%20the%20Dice%20with%20FXSL-htm.htm

Hope this helped.



=====
Cheers,

Dimitre Novatchev.
http://fxsl.sourceforge.net/ -- the home of FXSL

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