"Martin Lormes" <martin dot lormes at gmx dot net> wrote:
In XSLT 1.0
How do I select a random node from the source-tree or from an
external
document?
I was thinking of an XPath expression like this:
document('funnies.xml')/funnies/quote[random()]
Can I avoid using extension elements?
Yes, use the "randNext" template from FXSL.
More information is contained in the article:
"Casting the Dice with FXSL: Random Number Generation Functions in
XSLT"
http://fxsl.sourceforge.net/articles/Random/Casting%20the%20Dice%20with%20FXSL-htm.htm
Hope this helped.
=====
Cheers,
Dimitre Novatchev.
http://fxsl.sourceforge.net/ -- the home of FXSL
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