No, the simplest solution is to use normalize-space(), which
will remove
leading and trailing spaces, but won't take the space out of
"Rhode Island".
Very true - I must admit I wasn't really concentrating on the fix to the
problem, more the poor structure of the data. As Trevor said 'difficult
programming tasks are often the result of imperfect design' and in this
case by far the best solution is to modify the data (just like the
parenthesis issue).
-----Original Message-----
From: Mike Brown [mailto:mike(_at_)skew(_dot_)org]
Sent: 25 September 2002 16:50
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: Re: [xsl] xsl string comparison fails why?
Andrew Welch wrote:
The simplest solution that fits your stylesheet is to
translate() out
any whitespace from the text() content of the <state>
element before it
gets compared to the parameter:
<xsl:for-each select="admissions/state/text()">
<xsl:if test="translate(.,'	

 ','')=$state">
<xsl:value-of select="."/>
</xsl:if>
</xsl:for-each>
No, the simplest solution is to use normalize-space(), which
will remove
leading and trailing spaces, but won't take the space out of
"Rhode Island".
And the for-each is not strictly needed.
<xsl:value-of
select="admissions/state[normalize-space(text())=$state]"/>
will give him what he asked for, although I suspect that what
he *wants*
is something like
<xsl:for-each
select="admissions/state[normalize-space(text())=$state]"/>
<a href="{statelink/@href}">
<xsl:value-of select="statelink"/>
</a>
</xsl:for-each>
where the for-each is just shifting the context to make the subsequent
statelink references easier (you could use xsl:variable and
$foo/statelink if
you wanted)
- Mike
______________________________________________________________
______________
mike j. brown | xml/xslt: http://skew.org/xml/
denver/boulder, colorado, usa | resume:
http://skew.org/~mike/resume/
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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