oh ic what u mean.. then in such a case , how do we run a for loop for an
imported xml file???
for.example
if i get the locations from running a for-each to mainxml.xml
and get hold of the first univ-xml's name..
<xsl:for-each select="document(/univ-xml-list/univ-xml)">
<xsl:variable name = "external-xml" select ="document(.)"/>
</xsl:for-each>
Now is there a way to run a for-each for this external xml file??
so that i get hold of EACH ELEMENT in the External XML?? and get hold of
their properties like name() position() etc??
From: David Carlisle <davidc(_at_)nag(_dot_)co(_dot_)uk>
Reply-To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
CC: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: Re: [xsl] document() loops
Date: Fri, 13 Sep 2002 10:19:21 +0100
<xsl:for-each select="document(/univ-xml-list/univ-xml[1])">
<xsl:variable name = "element-name" select="name(.)"/>
<xsl:element name="$element-name">
</xsl:element>
</xsl:for-each>
this will create all the elements that are in the first elements..
No it won't as I said before that for-each is iterating over a single node
so it will only create one element, with name equal to teh name of teh
node selected in the xsl:for-each select=" however that node is a
document node, so has name "" so the xsl:eleemnt should generate an
error thatyou are trying to generate an element with an invalid name,
"".
David
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