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Re: document() loops

2002-09-13 02:19:21

  <xsl:for-each select="document(/univ-xml-list/univ-xml[1])">
  <xsl:variable name = "element-name" select="name(.)"/>
  <xsl:element name="$element-name">
  
  
  </xsl:element>
  </xsl:for-each>
  this will create all the elements that are in the first elements..

No it won't as I said before that for-each is iterating over a single node
so it will only create one element, with name equal to teh name of teh
node selected in the xsl:for-each select=" however that node is a
document node, so has name "" so the xsl:eleemnt should generate an
error thatyou are trying to generate an element with an invalid name,
"".


David

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