This should parse the numeric value and sort, which it does
fine, except that all the attributes are stripped off the output.
<xsl:template match ="I1/@* |I1">
<xsl:if test="I1/@i44='N'">
<xsl:copy>
<xsl:apply-templates select="@* | I1">
<xsl:sort select="@i29"
data-type="number" order="descending"/>
</xsl:apply-templates>
</xsl:copy>
</xsl:if>
</xsl:template>
Atrtibute nodes will match the above template rule but fail the <xsl:if>
test, so they will produce no output.
I need to perform a different sort if test ='Y' for the same
attribute node, moving the entire record to another section
of the document. that would look something like this.
You may need to use the substring() trick:
concat(substring(@i44, 1 div (test='N')),
substring(@i25, 1 div (test='Y'))
If test='Y' this is
concat(subtring(@i44, infinity), substring(@i25, 0))
which is string(@i25)
while if test='N' it is string(@i44).
Michael Kay
Software AG
home: Michael(_dot_)H(_dot_)Kay(_at_)ntlworld(_dot_)com
work: Michael(_dot_)Kay(_at_)softwareag(_dot_)com
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