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On Friday 25 October 2002 00:47, Ragulf Pickaxe wrote:
"xxx:node-set($Test)/node[1]".
But... is it then not possible to build a nodeset directly in the XSL? What
is the difference between doing thus and the example that I had in the
orriginal mail?
No, it's not currently possible with standard processors. The difference is
that you were creating a Result Tree Fragment (RTF), which is not the same as
a node-set.
All you can do with an RTF is <xsl:copy-of/> and <xsl:value-of/>. The idea is
(was) that you can create an RTF as the value of a variable and re-use it
throughout your stylesheet. For example, in HTML you might have some special
code to output a bullet point with pretty graphics, and you want to re-use
that code with the exact same <img> tag.
You cannot select children of an RTF. To do that, you have to convert it to a
node-set. Processor designers realized the pain of doing this, so they
provide xxx:node-set() functions to do the conversion. Unfortunately, the
functions are not compatible between processors, so you will have to do some
tricks if you want to use more than one processor.
With the example I do not need any conversions between anything.
Well, go complain to the XSLT 1.0 designers :). XSLT 2.0 doesn't have this
problem, since so many people like yourself have complained.
I believe that Saxon 7.0 is the only browser that supports XSLT 2.0. You can
go try that, get RTF to node-set conversion, and a bunch of other new
features for free.
- --
Peter Davis
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