But you solved the problem from the wrong direction ;-) The template below
is partly already implemented as so called built-in template. Another built-in
template, which is causing your problems, looks like following:
<xsl:template match="text()">
<xsl:value-of select="."/>
</xsl:template>
So you must simply overwrite this template:
<xsl:template match="text()"/>
Regards,
Joerg
Hi,
I solve the problem. Only was to add:
<xsl:template match="node()">
<xsl:apply-templates>
</xsl:template>
And with this, only the templates that I've defined works, and the text
of the
html does't appear.
A lot of thanks,
Marcial
Missatge citat per: Vasu Chakkera <vasucv(_at_)hotmail(_dot_)com>:
Your problem will be more clear if you can let us know what you "were"
expecting and what you "are" getting.
Vasu
----- Original Message -----
From: "Marcial Atienzar Navarro" <maratna(_at_)teleco(_dot_)upv(_dot_)es>
To: <xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com>
Sent: Monday, October 21, 2002 12:26 PM
Subject: [xsl] how to make default actions?
Hello,
I need to apply templates only for one type of nodes and for another
I
don't
want to make nothing.
For example:
<html>
<body>
<span>Hello world</span>
<img src=""/>
</body>
</html>
(This is a small example)
And the xsl is:
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
xmlns:html="http://www.w3.org/1999/xhtml";>
<xsl:output method="html"/>
<xsl:template match="html">
<html>
<body>
<xsl:apply-templates/>
</body>
</html>
</xsl:template>
<xsl:template match="span">
OK
</xsl:template>
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