--- Vic Gar wrote:
Hello all,
With flat-ish xml (below), I need to
1) select the elements from a predetermined position (e.g, elems
d1-d9)
<xsl:variable name="table_nodes" select="/a/b/c/*[position()
<
10]"/>
2) take those that have text node children
...and normalize-space{.}
3) make a table with rows of two name/value pairs (e.g.,
<tr><td>#9</td><td>foo</td><td>#10</td><td>bar</td></tr> )
for-each select="$table_nodes[position() mod 2 = 1]
<tr>
<xsl:apply-templates select=". | ...
4) if there are an odd number of elements, only the last row of the
table
can be missing a <td> - all the preceding rows should have the
requisite 2
name/value pairs.
I tried:
<xsl:apply-templates select=". | $table_nodes[position() > $here
and
position() < $here+2]" mode="td"/>
The nodes that made it into $table_nodes, in doc order, are
d1 & d4-9.
but for some reason it created:
d1 (d1 value} d4 (d4 value}
d5 (d5 value}
d6 (d6 value} d7 (d7 value)
d7 (d7 value} d9 (d9 value}
My understanding of what's going on here is a long way from where it
should
be. I get why d7 was selected twice, but as for the rest (why no d8,
why
single <td> at d5, how to do this properly) can anyone explain it to
me?
xml:
<a>
<b>
<c>
<d1>one</d1>
<d2></d2>
<d3></d3>
<d4>four</d4>
<d5>five</d5>
<d6>six</d6>
<d7>seven</d7>
<d8>eight</d8>
<d9>nine</d9>
<d10>ten</d10>
</c>
</b>
</a>
Many thanks!
Hi Vic,
Here's one solution to your problem:
With your source xml document (just above),
the following transformation:
============================
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="html" indent="yes"/>
<xsl:template match="/">
<table>
<xsl:apply-templates
select="/*/*/*/*[normalize-space()][position() mod 2 = 1]"
mode="row"/>
</table>
</xsl:template>
<xsl:template match="*" mode="row">
<tr>
<xsl:apply-templates select=".
|
following-sibling::*
[normalize-space()][1]"/>
</tr>
</xsl:template>
<xsl:template match="*">
<td><xsl:value-of select="name()"/></td>
<td><xsl:value-of select="."/></td>
</xsl:template>
</xsl:stylesheet>
when applied produces the desired result:
========================================
<table>
<tr>
<td>d1</td>
<td>one</td>
<td>d4</td>
<td>four</td>
</tr>
<tr>
<td>d5</td>
<td>five</td>
<td>d6</td>
<td>six</td>
</tr>
<tr>
<td>d7</td>
<td>seven</td>
<td>d8</td>
<td>eight</td>
</tr>
<tr>
<td>d9</td>
<td>nine</td>
<td>d10</td>
<td>ten</td>
</tr>
</table>
Hope this helped.
=====
Cheers,
Dimitre Novatchev.
http://fxsl.sourceforge.net/ -- the home of FXSL
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