Hello all,
With flat-ish xml (below), I need to
1) select the elements from a predetermined position (e.g, elems d1-d9)
<xsl:variable name="table_nodes" select="/a/b/c/*[position() <
10]"/>
2) take those that have text node children
...and normalize-space{.}
3) make a table with rows of two name/value pairs (e.g.,
<tr><td>#9</td><td>foo</td><td>#10</td><td>bar</td></tr> )
for-each select="$table_nodes[position() mod 2 = 1]
<tr>
<xsl:apply-templates select=". | ...
4) if there are an odd number of elements, only the last row of the table
can be missing a <td> - all the preceding rows should have the requisite 2
name/value pairs.
I tried:
<xsl:apply-templates select=". | $table_nodes[position() > $here and
position() < $here+2]" mode="td"/>
The nodes that made it into $table_nodes, in doc order, are
d1 & d4-9.
but for some reason it created:
d1 (d1 value} d4 (d4 value}
d5 (d5 value}
d6 (d6 value} d7 (d7 value)
d7 (d7 value} d9 (d9 value}
My understanding of what's going on here is a long way from where it should
be. I get why d7 was selected twice, but as for the rest (why no d8, why
single <td> at d5, how to do this properly) can anyone explain it to me?
xml:
<a>
<b>
<c>
<d1>one</d1>
<d2></d2>
<d3></d3>
<d4>four</d4>
<d5>five</d5>
<d6>six</d6>
<d7>seven</d7>
<d8>eight</d8>
<d9>nine</d9>
<d10>ten</d10>
</c>
</b>
</a>
Many thanks!
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