if all the columns are going to be equal width then you can try this
<xsl:param name="cols"><xsl:value-of select="count(tr/td)" /></xsl:param>
<fo:table>
<fo:table-column column-width="2cm" number-columns-repeated="{$cols}" />
...
</fo:table>
----- Original Message -----
From: <Jaish_Kumar(_at_)apex(_dot_)soft(_dot_)net>
To: <XSL-List(_at_)lists(_dot_)mulberrytech(_dot_)com>;
<Jaish_Kumar(_at_)apex(_dot_)soft(_dot_)net>
Sent: Monday, October 14, 2002 11:54 PM
Subject: [xsl] [xsl-fo] generating the correct number of columns for a table
from html to xsl-fo
Jaish Kumar
Apex,Ph. no. 5351194,5351027 extn 141
" Pessimist always looks for difficulty in opportunity and Optimist
always
looks for opportunity in difficulty "
----- Forwarded by Jaish Kumar/Product/Apex on 14/06/2002 09:19 AM -----
"El Hage Camille"
<CAMILLE(_dot_)ELHAGE(_at_)fr(_dot_)glaverbe To:
<xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com>
l.com> cc:
Sent by: Subject: [xsl]
[xsl-fo] generating the correct
owner-xsl-list(_at_)lists(_dot_)mulber number of
columns
for a table from html to xsl-fo
rytech.com
14/10/2002 10:20 PM
Please respond to xsl-list
Hi all,
I need to generate a table in xsl-fo from an html table. My problem is
that
in FO, you need to declare the number of columns before starting the body.
On the FAQ, I only found the (enlightening) discussion on how to get the
maximum number of child nodes (
http://www.biglist.com/lists/xsl-list/archives/200101/msg00177.html), but
the resulting code gives a number and I don't know how to use that.
My question is: if I have a number (say "8"), how do I loop through to
generate 8 times the line : <fo:table-column column-width="2cm"/> ?
thanks for any help.
Camille
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list