Just as an FYI ...
I do all of my XSLT work in Visual XSLT, which is a VS.Net add-in. I
really enjoy using both tools ... Visual XSLT definitely has some nice
productivity-boosting features. Since I write C# the rest of the time,
it is nice to be able to stay in VS for XSLT ... and schema too ...
Visual XSLT uses the XML and XSLT namespace/classes in the .net
framework, although it can be made to use Xalan.
Back to the issue at hand ... you should be wary of using
normalize-space(). It is a pretty powerful tool that can be problematic
at times, or at least has been for me.
Given:
<para>here is some <inline>text</inline> as an
example</para>
Result after normalize-space:
<para>here is some<inline>text</inline>as an example</para>
What I'd really want:
<para>here is some <inline>text</inline> as an example</para>
Anyway, there are ways of handling this situation, but you have to be
careful.
Thanks,
Rich
-----Original Message-----
From: Macaulay,Malcolm (US)
[mailto:Malcolm(_dot_)Macaulay2(_at_)cnare(_dot_)com]
Sent: Thursday, October 10, 2002 2:13 PM
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Thanks Richard, Joerg, and Michael,
That works great. I did the transform using Instant Saxon and all the
tabs were gone. I need to have a play with MSXML in my application and
confirm that this works. I've been using XMLSpy, but this is misleading
me, because:
- XMLSpy indents (i.e. 'pretty-prints') the resulting XML if your use
it's 'Apply XSL' facility
- XMLSpy does not however format files which you open
Thanks again!
cheers
Malcolm
-----Original Message-----
From: Richard Lander [mailto:rlander(_at_)microsoft(_dot_)com]
Sent: Thursday, October 10, 2002 3:16 PM
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: RE: [xsl] removing tab formatting during XSLT?
Does this help?
<?xml version="1.0"?>
<xslt:stylesheet xmlns:xslt="http://www.w3.org/1999/XSL/Transform";
version="1.0">
<xslt:template match="/">
<xslt:apply-templates/>
</xslt:template>
<xslt:template match="node() | @*">
<xslt:copy>
<xslt:apply-templates select="node() | @*"/>
</xslt:copy>
</xslt:template>
<xslt:template match="text()">
<xslt:value-of select="normalize-space(.)"/>
</xslt:template>
</xslt:stylesheet>
Rich
-----Original Message-----
From: Macaulay,Malcolm (US)
[mailto:Malcolm(_dot_)Macaulay2(_at_)cnare(_dot_)com]
Sent: Thursday, October 10, 2002 1:01 PM
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Thanks Richard,
Still no go however. I changed my XLST to:
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
<xsl:output method="xml" version="1.0" encoding="UTF-8"
indent="no"/>
<xsl:strip-space elements="*"/>
<xsl:template match="/">
<xsl:apply-templates/>
</xsl:template>
<xsl:template match="*">
<!-- recreate the element -->
<xsl:element name="{name()}">
<xsl:apply-templates/>
</xsl:element>
</xsl:template>
<xsl:variable name="tab">	</xsl:variable>
<xsl:template match="text()">
<xsl:value-of select="translate(. , $tab , '')"/>
</xsl:template>
</xsl:stylesheet>
However the match="text()" template does not get invoked on the *
element below:
<?xml version="1.0"?>
<A>
*<B att="att">a</B>
<C>b</C>
<D>c</D>
</A>
I'm clearly misunderstanding this. Is there a text element in the *
position?
Any additional help would be greatly appreciated.
cheers
Malcolm
-----Original Message-----
From: Richard Lander [mailto:rlander(_at_)microsoft(_dot_)com]
Sent: Thursday, October 10, 2002 2:18 PM
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: RE: [xsl] removing tab formatting during XSLT?
I've done this sort of thing before ...
You have two problems, as I see it.
1- you are referencing a named entity (nbsp;) w/o really doing so. You
would need to use ' '. Still, that probably doesn't make any sense,
given that a non-breaking space isn't the same as a tab.
2. You should search on '	' instead. I'm pretty sure that that is
the tab character ...
Rich
-----Original Message-----
From: Macaulay,Malcolm (US)
[mailto:Malcolm(_dot_)Macaulay2(_at_)cnare(_dot_)com]
Sent: Thursday, October 10, 2002 10:55 AM
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Could someone please enlighten me on how I can remove tab formatting
from my resulting XML.
Here's an example:
Source XML:
<?xml version="1.0"?>
<A>
<B att="att">a</B>
<C>b</C>
<D>c</D>
</A>
Desired output XML (i.e. the same as input but with all tabs removed):
<?xml version="1.0"?><A><B att="att">a</B><C>b</C><D>c</D></A>
XSLT (which doesn't work):
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
<xsl:output method="xml" version="1.0" encoding="UTF-8"
indent="no"/>
<xsl:strip-space elements="*"/>
<xsl:template match="/">
<xsl:apply-templates/>
</xsl:template>
<xsl:template match="*">
<!-- recreate the element -->
<xsl:element name="{name()}">
<!-- copy existing attributes-->
<xsl:for-each select="@*">
<xsl:copy/>
</xsl:for-each>
<xsl:apply-templates/>
</xsl:element>
</xsl:template>
<xsl:variable name="tab">nbsp;</xsl:variable>
<xsl:template match="text()">
<xsl:value-of select="translate(. , $tab , '')"/>
</xsl:template>
<!-- original attempt
<xsl:template match="text()">
<xsl:value-of select="normalize-space(.)"/>
</xsl:template>
-->
</xsl:stylesheet>
I want to remove the tabs because this significantly reduces the size of
the file.
Thanks in advance.
cheers
Malcolm
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