RE: removing tab formatting during XSLT?

Does this help?

<?xml version="1.0"?> 
<xslt:stylesheet xmlns:xslt="http://www.w3.org/1999/XSL/Transform"; 
version="1.0">

        <xslt:template match="/">
                <xslt:apply-templates/>
        </xslt:template>
        
        <xslt:template match="node() | @*">
                <xslt:copy>
                        <xslt:apply-templates select="node() | @*"/>
                </xslt:copy>
        </xslt:template>

        <xslt:template match="text()">
                <xslt:value-of select="normalize-space(.)"/>
        </xslt:template>        

</xslt:stylesheet>

Rich 
 
-----Original Message-----
From: Macaulay,Malcolm (US) 
[mailto:Malcolm(_dot_)Macaulay2(_at_)cnare(_dot_)com] 
Sent: Thursday, October 10, 2002 1:01 PM
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com

Thanks Richard,

Still no go however. I changed my XLST to:

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
        
        <xsl:output method="xml" version="1.0" encoding="UTF-8" indent="no"/>
        
        <xsl:strip-space elements="*"/>
        
        <xsl:template match="/">
                <xsl:apply-templates/>
        </xsl:template>
        
        <xsl:template match="*">
                <!-- recreate the element -->
                <xsl:element name="{name()}">
                        <xsl:apply-templates/>
                </xsl:element>
        </xsl:template>
        
        <xsl:variable name="tab">&#x9;</xsl:variable>
        
        <xsl:template match="text()">
                <xsl:value-of select="translate(. , $tab , '')"/>
        </xsl:template>

</xsl:stylesheet> 

However the match="text()" template does not get invoked on the * element below:

<?xml version="1.0"?>
<A>
        *<B att="att">a</B>
        <C>b</C>
        <D>c</D>
</A>

I'm clearly misunderstanding this. Is there a text element in the * position?

Any additional help would be greatly appreciated.

cheers

Malcolm


-----Original Message-----
From: Richard Lander [mailto:rlander(_at_)microsoft(_dot_)com]
Sent: Thursday, October 10, 2002 2:18 PM
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: RE: [xsl] removing tab formatting during XSLT?


I've done this sort of thing before ... 

You have two problems, as I see it.

1- you are referencing a named entity (nbsp;) w/o really doing so. You would 
need to use '&nbsp;'. Still, that probably doesn't make any sense, given that a 
non-breaking space isn't the same as a tab.

2. You should search on '&#x9;' instead. I'm pretty sure that that is the tab 
character ...

Rich
 
-----Original Message-----
From: Macaulay,Malcolm (US) 
[mailto:Malcolm(_dot_)Macaulay2(_at_)cnare(_dot_)com] 
Sent: Thursday, October 10, 2002 10:55 AM
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com

Could someone please enlighten me on how I can remove tab formatting from my 
resulting XML.

Here's an example:

Source XML:

<?xml version="1.0"?>
<A>
        <B att="att">a</B>
        <C>b</C>
        <D>c</D>
</A>

Desired output XML (i.e. the same as input but with all tabs removed):

<?xml version="1.0"?><A><B att="att">a</B><C>b</C><D>c</D></A>

XSLT (which doesn't work):

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
        <xsl:output method="xml" version="1.0" encoding="UTF-8" indent="no"/>
        
        <xsl:strip-space elements="*"/>
        
        <xsl:template match="/">
                <xsl:apply-templates/>
        </xsl:template>
        
        <xsl:template match="*">
                <!-- recreate the element -->
                <xsl:element name="{name()}">
                        <!-- copy existing attributes-->
                        <xsl:for-each select="@*">
                                <xsl:copy/>
                        </xsl:for-each>
                        <xsl:apply-templates/>
                </xsl:element>
        </xsl:template>
        
        <xsl:variable name="tab">nbsp;</xsl:variable>
        
        <xsl:template match="text()">
                <xsl:value-of select="translate(. , $tab , '')"/>
        </xsl:template>

        <!-- original attempt   
        <xsl:template match="text()">
                <xsl:value-of select="normalize-space(.)"/>
        </xsl:template>
        -->
 
</xsl:stylesheet>

I want to remove the tabs because this significantly reduces the size of the 
file.

Thanks in advance.

cheers

Malcolm

 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list




 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list


 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list




 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list