xsl-list
[Top] [All Lists]

Re: calculate unique items in xsl

2002-10-10 13:13:16
Yes, <xsl:key> (Muenchian Method) is a good approach for your grouping problem:

<xsl:key name="items" match="item" use="warehousecode"/>

<xsl:template match="inventory">
Number of unique warehouse codes: <xsl:value-of select="count(item[generate-id() = generate-id(key('items', warehousecode))])"/>
</xsl:template>

(untested)

Regards,

Joerg

RJ P wrote:

Thanks for your help in my previous post! Given the below xml,how can I get the
the number of unique warehouse codes?  Do I need to use <xsl:key>?

<inventory>
<item>
<warehousecode>BA</warehousecode>
<item>bolt</item>
<quantity>34</quantity>
</item>
<item>
<warehousecode>BA</warehousecode>
<item>nail</item>
<quantity>50</quantity>
</item>
<item>
<warehousecode>AC</warehousecode>
<item>tack</item>
<quantity>5</quantity>
</item>
<item>
<warehousecode>BA</warehousecode>
<item>hammer</item>
<quantity>10</quantity>
</item>
<item>
<warehousecode>AD</warehousecode>
<item>screwdriver</item>
<quantity>60</quantity>
</item>
<item>
<warehousecode>AB</warehousecode>
<item>wrench</item>
<quantity>13</quantity>
</item>
</inventory>

Desired output:

Number of unique warehouse codes:  4

Thanks for helping an xsl newbie!!

RJ


XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list



<Prev in Thread] Current Thread [Next in Thread>