Andrew Welch wrote:
preceding-sibling::node()[normalize-space()][1][self::comment()]
This will select the first in a list of nodes that return true for
normalize-space() and self::comment().
No, that would be
preceding-sibling::node()[normalize-space()][self::comment()][1]
What you have,
preceding-sibling::node()[normalize-space()][1][self::comment()]
selects the first non-whitespace-text node if it is a comment.
Sure. But aren't they both the same (they select the same node)? The
only difference would be the size of the lists the predicates create?
(feel free to point out the correct terminology here)
Definitely no.
<root>
<!-- test -->
<test1>test</test1>
<test2>test</test2>
<!-- test -->
<test3>test</test3>
<test4>test</test4>
</root>
with context test4:
preceding-sibling::node() gets all other test elements and the comments and
the whitespace only text nodes.
preceding-sibling::node()[normalize-space()] gets all other test elements
and the comments.
preceding-sibling::node()[normalize-space()][1] gets test3.
preceding-sibling::node()[normalize-space()][1][self::comment()] gets
nothing, because test3 isn't a comment.
preceding-sibling::node()[normalize-space()][self::comment()] gets all comments.
preceding-sibling::node()[normalize-space()][self::comment()][1] gets the
comment infront of test3.
But the original poster asked for immediately preceding comments. So only
preceding-sibling::node()[normalize-space()][1][self::comment()] is correct
- with the danger of empty elements.
Regards,
Joerg
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