Re: Selecting multi-existant elements only once

Your problem is to print unique nodes.
You could do that the way you found out yourself or make use of keys , which
is more efficient.
Refer to the articles at Jeni's Page

http://www.jenitennison.com/xslt/grouping/index.html

HTH
Vasu
----- Original Message -----
From: "Sorin Marti" <mas(_at_)semafor(_dot_)ch>
To: <xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com>
Sent: Monday, November 25, 2002 3:30 PM
Subject: Re: [xsl] Selecting multi-existant elements only once


> I've got the solution...sorry for asking...
>
>  <xsl:for-each
select="//departement/profession[not(desc=preceding::desc)]">
>    <xsl:value-of select="desc"/>
>   </xsl:for-each>
>
> Sorin Marti
>
> I wrote:
>
> > Hi all,
> >
> > I've got a XML-File with following structure. There are different
> > departements and in each departement there are different professions.
> > I want to have every profession of all departement once... If there is
> > a Manager in departement a and departement b, "Manager" should only be
> > printed out once...
> >
> > How can I do that?
> >
> > [...]
> > <departement>
> >  <profession>
> >    <desc>Manager</desc>
> >    <salary>5000</salary>
> >  </profession>
> >
> >  <profession>
> >    <desc>Assistant</desc>
> >    <salary>3000</salary>
> >  </profession>
> >
> >  <profession>
> >    <desc>Employee</desc>
> >    <salary>2000</salary>
> >  </profession>
> > </departement>
> >
> > <departement>
> >  <profession>
> >    <desc>Manager</desc>
> >    <salary>5000</salary>
> >  </profession>
> >
> >  <profession>
> >    <desc>Worker</desc>
> >    <salary>2000</salary>
> >  </profession>
> > </departement>
> >
> > [...]
> >
> > Thanks for your help !
> >
> > Sorin
> >
> >
> > XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list
>
>
>  XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list
 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list