Or you could use xsl:key, which is quicker and very useful.
cheers,
Tom SW
-----Original Message-----
From: Sorin Marti [mailto:mas(_at_)semafor(_dot_)ch]
Sent: 25 November 2002 15:30
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: Re: [xsl] Selecting multi-existant elements only once
I've got the solution...sorry for asking...
<xsl:for-each
select="//departement/profession[not(desc=preceding::desc)]">
<xsl:value-of select="desc"/>
</xsl:for-each>
Sorin Marti
I wrote:
Hi all,
I've got a XML-File with following structure. There are different
departements and in each departement there are different
professions.
I want to have every profession of all departement once...
If there is
a Manager in departement a and departement b, "Manager"
should only be
printed out once...
How can I do that?
[...]
<departement>
<profession>
<desc>Manager</desc>
<salary>5000</salary>
</profession>
<profession>
<desc>Assistant</desc>
<salary>3000</salary>
</profession>
<profession>
<desc>Employee</desc>
<salary>2000</salary>
</profession>
</departement>
<departement>
<profession>
<desc>Manager</desc>
<salary>5000</salary>
</profession>
<profession>
<desc>Worker</desc>
<salary>2000</salary>
</profession>
</departement>
[...]
Thanks for your help !
Sorin
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