Robin,
At 09:41 AM 11/21/2002, you wrote:
XPATH help appreciated !
XML:
<A>
<B>
<C>101</C>
<D>
<E W="XYZ">0204268270</E>
<F>
<G>Versicherungsstr. 1</G>
<H>Offenburg</H>
</F>
</E>
</D>
</B>
</A>
XSL:
<xsl:template match="A">
<xsl:for-each
select="./*[1]//*[not(*)]|./*[1]//@*[not(*)]">
<xsl:value-of select="name()"/>
<xsl:if test="position()!=last()">;</xsl:if>
</xsl:for-each>
<xsl:apply-templates/>
</xsl:template>
This gives me output of: C;E;W;G;H
Question 1: Can I get both attribute-names and element-names more easily in
the select or does it have to be like I have it above ?
Well, since attributes never have children you could say
select=" *[1]//*[not(*)] | *[1]//@*]"
which is a *little* easier.
It gets leaf node descendants of the first child element, plus all
attributes on the first child or its descendants. Is this what you want? If
you want only attributes on the leaf nodes that'll be "*[1]//*[not(*)] |
*[1]//*[not(*)/@*", but in that case I'd think it'd be better first to
select the leaves, then in a template get their attributes.
Question 2: How can I exclude the descendants of element F from the select
? Output would then be C;E;W. I've tried various combinations but either end
up with all-or-nothing.
You can exclude nodes that have an F ancestor by grouping with () and
qualifying the group with another predicate:
select="(*[1]//*[not(*)] | *[1]//@*)[not(ancestor::F)]"
Cheers,
Wendell
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