I'll take a shot at answering this.
How do I obtain and copy the node <adesc> of File2 using the above
$path variable? Something like the below one:
<xsl:template match="node()">
<xsl:copy-of select="document(File2.xml)/$path.."/>
</xsl:template>
I assume that you want to process file 1, but cross check in file 2 for
additional elements to copy into file 1. You want to use an XPath
expression like element[1]/child[1]/a[1] (note I have added positions) to
reference the appropriate point in file 2. Is my understanding correct?
You can't evaluate dynamic XPath expressions in the body of a select clause.
So what you have written won't work. If the structure element/child/a is
fixed, you could use a nasty expression like
<xsl:template match="a">
<xsl:copy-of
select="document(File2.xml)/element[position()=count(current()/../../precedi
ng-sibling::element)+1]/child[position()=count(current()/../preceding-siblin
g::child)+1]/a[position()=count(current()/preceding-sibling::a)+1]/adesc"/>
</xsl:template>
There are probably 2 other ways that I can think of for solving this
problem, but I can't address and test them right now. I might try and post
a follow up message later.
Hope this helps,
James Carlyle
www.takepart.com
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list