xsl-list
[Top] [All Lists]

Re: sorting based on a variable

2002-11-12 15:41:09
Do you use an older Xalan version (e.g. 2.2)? A few days ago I had the same problem with such an old version. Try "data[position() = $column]". You can also try Michael's suggestion using number($column), maybe there is only a problem with the evaluating $column to a number.

Joerg

Kasper Nielsen wrote:
hi (another question)

lets say I want to some data for the $column data-column

<projects>
  <project name="a">
    <data> 1237</data>
    <data> 1234</data>
    <data> 1235</data>
    <data> 1236</data>
  </project>
  <project name="b">
    <data> 12</data>
    <data> 41234</data>
    <data> 51235</data>
    <data> 71236</data>
  </project>
  <project name="c">
    <data> 1</data>
    <data> 41234</data>
    <data> 51235</data>
    <data> 71236</data>
  </project>
</projects>

so if $column=1 then it would sort them into {project name="c", project
name="b", project name="a"}
however i've tried
<xsl:for-each select="projects/project">
    <xsl:sort select="./data[$column]" data-type="number"/>
but it doesn't work?
however if just use something like
    <xsl:sort select="./data[1]" data-type="number"/> it works fine

anyone can tell me what im doing wrong?

regards
  Kasper Nielsen


XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list



<Prev in Thread] Current Thread [Next in Thread>