RE: sorting based on a variable

See FAQ at

http://www.dpawson.co.uk/xsl/sect2/nono.html#d1243e407

Hope this helps,
John Pallister
jpallister(_at_)engenius(_dot_)com

-----Original Message-----
From: Kasper Nielsen [mailto:news(_at_)kav(_dot_)dk]
Sent: Tuesday, November 12, 2002 9:34 AM
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] sorting based on a variable


hi (another question)

lets say I want to some data for the $column data-column

<projects>
  <project name="a">
    <data> 1237</data>
    <data> 1234</data>
    <data> 1235</data>
    <data> 1236</data>
  </project>
  <project name="b">
    <data> 12</data>
    <data> 41234</data>
    <data> 51235</data>
    <data> 71236</data>
  </project>
  <project name="c">
    <data> 1</data>
    <data> 41234</data>
    <data> 51235</data>
    <data> 71236</data>
  </project>
</projects>

so if $column=1 then it would sort them into {project name="c", project
name="b", project name="a"}
however i've tried
<xsl:for-each select="projects/project">
    <xsl:sort select="./data[$column]" data-type="number"/>
but it doesn't work?
however if just use something like
    <xsl:sort select="./data[1]" data-type="number"/> it works fine

anyone can tell me what im doing wrong?

regards
  Kasper Nielsen


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