Hello,
I'm using jstl to parse the file. With this parser I can pass param to the xsl
by the way:
<x:transform xml="${xmldocument}" xslt="${xslt}">
<x:param name="nodo_id" value="${nodo_id}"/>
<x:param name="almacen_id" value="${almacen_id}"/>
<x:param name="modalidad" value="${modalidad}"/>
</x:transform>
and after that I can take them on the xsl by this:
<xsl:param name="nodo_id"></xsl:param>
<xsl:param name="almacen_id"></xsl:param>
<xsl:param name="modalidad"></xsl:param>
<xsl:param name="prueba"/>
how Jarno has reply on his email.
Marcial
Missatge citat per: Steve Clay <steve(_dot_)clay(_at_)venation(_dot_)com>:
Hi
I've been struggling with this too. I have some xml which I want to
display in a browser, having transformed it to html using xslt. The
stylesheet needs to select just some of the data: which data exactly is
known only at runtime. So ideally I'd like to pass a parameter on the
url like you can do with html pages:
(a) html like this: "http://somewhere/myhtmlpage.htm?some-param.
(b) xml like this?: "file:///c:\path\filename.xml?some-param
I have managed to do this by 1) having a real html file with a body
consisting of a single <div/> element, (2) loading the xml file, (3)
creating a new node, (4) extracting the url parameter using the
javascript "document.location.search.substring(1);", (5) setting the new
node's value to this parameter and finally (5) loading the xslt, which
can now access the node I just added and use it to select just the data
required before assigning it to the <div> element in the body of the
page. Phew! Is there an easier and more elegant way?
On this topic Jarno.Elovirta said "Top-level xsl:param element with the
same name." I wondered if this meant I could just put "<?xml-stylesheet
type="text/xsl" href="Data.xslt"?> at the top of my xml file and load it
in Explorer using something like (b) above but if I have a stylesheet
with a parameter element at the top level MXSML v4.0 just says "Keyword
xsl:stylesheet may not contain xsl:parameter." So, I'm sorry Jarno but I
don't understand what you meant.
Anyone any suggestions or ideas please?
Kindest regards.
Steve Clay
-----Original Message-----
From: Jarno(_dot_)Elovirta(_at_)nokia(_dot_)com
[mailto:Jarno(_dot_)Elovirta(_at_)nokia(_dot_)com]
Sent: 04 November 2002 07:31
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: RE: [xsl] How to obtain parameters with the xsl?
Hi,
I need to obtain parameters with the xsl. How can I do it?
I'm using xalan o
jstl to make the parser, and I know how to pass the
parameters, but i don't know
how to obatin them.
Top-level xsl:param element with the same name.
Cheers,
Jarno
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