Jan Krattiger wrote:
i use xsl:sort to sort the output. now i need something like xsl:number to
give the elements numbers from 1-n, but i need the sorted one to be
numbered.
xsl:number uses the unsorted, "original" xml to number. one possiblity would
be sorting the xml before transforming... but that not possible in my case..
does anyone have a solution?
Well, temporary tree aka result tree fragment? That's obviously not a very
effective, but at least simple and clear solution - first sort to the
variable, then convert it to a nodeset and process using xsl:number.
--
Oleg Tkachenko
eXperanto team
Multiconn Technologies, Israel
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list