"Robert Koberg" <rob(_at_)koberg(_dot_)com> wrote in message
news:ADECJLDNBFNBOJBLKCMOKEFPDMAA(_dot_)rob(_at_)koberg(_dot_)com(_dot_)(_dot_)(_dot_)
Hi bix,
I think everyone is getting caught up in your explicit question :)
and not
understanding what you want, or perhaps I am missing something...
Based on previous examples:
concat($node,'/',$type,'/item') -- assuming $type is the name of an
element
select="'someBranch'" -- assuming 'someBranch' is the name of an
element
this is very simple to solve in XSLT 1.0, as I posted earlier:
<xsl:template name="foo">
<xsl:param name="node"/>
<xsl:param name="branch" select="'someBranch'"/>
<xsl:for-each select="$node/*[name()=$branch]/leaf">
<xsl:value-of select="@id" />
</xsl:for-each>
</xsl:template>
best,
-Rob
This is what I advised him to do in one of the newsgroups about a week
ago. But obviously this person has some other requirements.
How long will need 1000 people to guess?
From my empirical observations more than 50% of the messages and time
taken goes in clarifying the formulation of a problem -- some never get
explained well.
=====
Cheers,
Dimitre Novatchev.
http://fxsl.sourceforge.net/ -- the home of FXSL
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