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RE: combining two variables to generate XPATH

2002-12-17 12:40:58
I believe this is not possible.  XSLT doesn't allow you
to use a variable for an XPath expression.  See number 2 at
the following list:

http://www.dpawson.co.uk/xsl/sect2/nono.html

-----Original Message-----
From: bix xslt [mailto:bix_xslt(_at_)hotmail(_dot_)com]
Sent: Tuesday, December 17, 2002 1:32 PM
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: Re: [xsl] combining two variables to generate XPATH


Please note I made a slight correction.  the $node that 
appears within the 
foreach statment just under the branch variable assignment 
should be $branch 
instead.  This does not solve my problem - this is the 
original problem.  
Thanks.


From: "bix xslt" <bix_xslt(_at_)hotmail(_dot_)com>
       <xsl:variable name="branch" 
select="concat($node,'/',$type,'/item')" />
       <xsl:value-of select="$branch" />
<!--        <xsl:for-each select="$node">

becomes

       <xsl:variable name="branch" 
select="concat($node,'/',$type,'/item')" />
       <xsl:value-of select="$branch" />
<!--        <xsl:for-each select="$branch">


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