I believe this is not possible. XSLT doesn't allow you
to use a variable for an XPath expression. See number 2 at
the following list:
http://www.dpawson.co.uk/xsl/sect2/nono.html
-----Original Message-----
From: bix xslt [mailto:bix_xslt(_at_)hotmail(_dot_)com]
Sent: Tuesday, December 17, 2002 1:32 PM
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: Re: [xsl] combining two variables to generate XPATH
Please note I made a slight correction. the $node that
appears within the
foreach statment just under the branch variable assignment
should be $branch
instead. This does not solve my problem - this is the
original problem.
Thanks.
From: "bix xslt" <bix_xslt(_at_)hotmail(_dot_)com>
<xsl:variable name="branch"
select="concat($node,'/',$type,'/item')" />
<xsl:value-of select="$branch" />
<!-- <xsl:for-each select="$node">
becomes
<xsl:variable name="branch"
select="concat($node,'/',$type,'/item')" />
<xsl:value-of select="$branch" />
<!-- <xsl:for-each select="$branch">
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