I have to thank for your input.
The next problem I have is to choose which solution I take ;-)
All of them are working.
Thanx
----- Original Message -----
From: "Francis Norton" <francis(_at_)redrice(_dot_)com>
To: <xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com>
Sent: Wednesday, January 22, 2003 11:34 AM
Subject: Re: [xsl] calculating pow of numbers and a final sum
Hi Andreas,
I think that this is one of those occasions wher you do need to use
recursion - I can't (at this time of morning) see any way of doing it
with a simple XPath maths expression, or even XPath numeric expressions
inside a loop.
Try something like this -
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="text"/>
<!-- case conversion variables -->
<xsl:variable name="abc">abcdefghijklmnopqrstuvwxyz</xsl:variable>
<xsl:variable name="ABC">ABCDEFGHIJKLMNOPQRSTUVWXYZ</xsl:variable>
<!-- kick off recursive transform -->
<xsl:template match="logging">
<xsl:apply-templates select="target[1]"/>
</xsl:template>
<!-- simple tail-end recursive transform -->
<xsl:template match="target">
<xsl:param name="base" select="1" />
public static final int <xsl:value-of select="translate(@name,
$abc, $ABC)" /> = <xsl:value-of select="$base" />;
<xsl:apply-templates select="following-sibling::target[1]">
<xsl:with-param name="base" select="$base * 2" />
</xsl:apply-templates>
</xsl:template>
</xsl:stylesheet>
Using recursion to step through a sequence of elements, one by one, is
in fact a helpful in many cased where you need to perform arbitrary
cumulative operations which can't be done using numeric operators,
sum(), position() or xsl:number, for instance in reports.
Francis.
--
"Never mind manoeuvre, go straight at 'em." - Admiral Horatio Nelson
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