You can eliminate the unused namespaces using exclude-result-prefixes.
For the namespaces that are actually used in an element or attribute
name in the result tree, you will have to generate them with a different
name.
-----Original Message-----
From: owner-xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
[mailto:owner-xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com] On Behalf Of
Andrey Solonchuk
Sent: 13 January 2003 11:13
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] How I could produce xml without xmlns:* ???
Hello xsl-list,
How I could produce xml without xmlns:*
I use the xsl
<?xml version='1.0'?>
<xsl:stylesheet
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"; version="1.0"
xmlns:xalan="http://xml.apache.org/xalan";
xmlns:my="http://my";
xmlns:axsl="http://www.w3.org/1999/XSL/TransformAlias";
exclude-result-prefixes="xalan my xsl xmlns axsl">
<xsl:namespace-alias stylesheet-prefix="axsl" result-prefix="xsl"/>
<xsl:output method="xml" indent="yes" xalan:indent-amount="5"/>
<xsl:key name="test" match="field" use="."/>
<my:import>
<field id="1">11</field>
<field id="2">11</field>
<field id="3">12</field>
</my:import>
<xsl:template match="/">
<xsl:copy-of select="document('')//my:import/"/>
</xsl:template>
</xsl:stylesheet>
and in output I get the next
<?xml version="1.0" encoding="UTF-8"?>
<my:import xmlns:my="http://my"; !!!!!!
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"; !!!!!!
xmlns:xalan="http://xml.apache.org/xalan"; !!!!!!
xmlns:axsl="http://www.w3.org/1999/XSL/TransformAlias";> !!!!!!
<field id="1">11</field>
<field id="2">11</field>
<field id="3">12</field>
</my:import>
--
Best regards,
Andrey mailto:solo(_at_)ibis(_dot_)odessa(_dot_)ua
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