Andrey Solonchuk wrote:
How I could produce xml without xmlns:*
I use the xsl
<?xml version='1.0'?>
<xsl:stylesheet
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"; version="1.0"
xmlns:xalan="http://xml.apache.org/xalan";
xmlns:my="http://my";
xmlns:axsl="http://www.w3.org/1999/XSL/TransformAlias";
exclude-result-prefixes="xalan my xsl xmlns axsl">
<xsl:namespace-alias stylesheet-prefix="axsl" result-prefix="xsl"/>
<xsl:output method="xml" indent="yes" xalan:indent-amount="5"/>
<xsl:key name="test" match="field" use="."/>
<my:import>
<field id="1">11</field>
<field id="2">11</field>
<field id="3">12</field>
</my:import>
<xsl:template match="/">
<xsl:copy-of select="document('')//my:import/"/>
That is syntax error btw, should be "document('')//my:import"
and in output I get the next
<?xml version="1.0" encoding="UTF-8"?>
<my:import xmlns:my="http://my"; !!!!!!
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"; !!!!!!
xmlns:xalan="http://xml.apache.org/xalan"; !!!!!!
xmlns:axsl="http://www.w3.org/1999/XSL/TransformAlias";> !!!!!!
<field id="1">11</field>
<field id="2">11</field>
<field id="3">12</field>
</my:import>
I believe you cannot. exclude-result-prefixes only affects literal result
elements, but your <my:import> is not such.
--
Oleg Tkachenko
eXperanto team
Multiconn Technologies, Israel
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list