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RE: Generating variable DOCTYPE

2003-01-16 04:43:10


-----Original Message-----
From: Yates, Danny (ANTS) [mailto:danny(_dot_)yates(_at_)ants(_dot_)co(_dot_)uk]
Sent: donderdag 16 januari 2003 12:02
To: 'xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com'
Subject: RE: [xsl] Generating variable DOCTYPE


Look at xsl:output
That's where my problem started. I want to pass the place of my DTD in a
parameter to the stylesheet.
But it's not possible to say <xsl:output method="xml" encoding="UTF-8"
doctype-system="{$DTDLocation}"/> (except in XSLT 1.1, but that never became
a recommendation, so I want to avoid to use that). That's were the whole
problem started.

Ismaël


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