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Re: Re: Re: Can one _generate_ namespace nodes?

2003-02-25 13:07:01

"Joseph Kesselman" <keshlam(_at_)us(_dot_)ibm(_dot_)com> wrote in message
news:OFAE3EAC25(_dot_)E1215AC5-ON85256CD8(_dot_)004D468A-85256CD8(_dot_)004E5301(_at_)us(_dot_)ibm(_dot_)com(_dot_)(_dot_)(_dot_)
Quoth "Dimitre Novatchev" <dnovatchev(_at_)yahoo(_dot_)com>
What about the following:

...
 <xsl:template match="/">
  <newxsl:stylesheet version="1.0"
    xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
     <newxsl:text>foo</newxsl:text>
  </newxsl:stylesheet>
 </xsl:template>

Hmmmmmm. That uses a literal result element with explicit namespace
declaration attribute to work around the limitation on <xsl:attribute>.
Looks like it might actually do the trick... though it's just subtle
enough that I'm not sure I want to take the time to teach it. <smile/>


Yes, this is the simplest possible way to do the job. All other ways involve
some kind of a trick -- e.g. copying artificial attributes.



=====
Cheers,

Dimitre Novatchev.
http://fxsl.sourceforge.net/ -- the home of FXSL





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