Newby Question reformatting xml

I am new to XSL and trying to get a grasp of the language. I need to 
totally reformat some xml files and have a question about node paths.
Example XML file:

<?xml version="1.0" encoding="UTF-8"?>
<AAA>
        <DDD id="test1">
                <BBB>10</BBB>
                        <CCC>ccc</CCC>
                <BBB>5</BBB>
                <BBB>7</BBB>
        </DDD>
        <DDD id="test2">
                <BBB>1</BBB>
                <BBB>2</BBB>
                        <CCC>ccc</CCC>
                <BBB>3</BBB>
        </DDD>
</AAA>

What I want to new XML file to look like:

<?xml version="1.0" encoding="UTF-8"?>
<AAA>
        <DDD>
                <BBB num="test1">10</BBB>
                <BBB num="test1">5</BBB>
                <BBB num="test1">7</BBB>
        </DDD>
        <DDD>
                <BBB num="test2">1</BBB>
                <BBB num="test2">2</BBB>
                <BBB num="test2">3</BBB>
        </DDD>
</AAA>

My XSL file:

<?xml version="1.0" encoding="UTF-8" ?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"; 
version="1.0">
        <xsl:output method="xml" indent="yes"/>
        
        <xsl:template match="AAA">
                <xsl:element name="AAA">
                        <xsl:apply-templates select="DDD" />
                </xsl:element>
        </xsl:template>
        
        <xsl:template match="DDD">
                <xsl:element name="DDD">
                        <xsl:apply-templates select="BBB"></xsl:apply-templates>
                </xsl:element>
                
        </xsl:template>
        
        <xsl:template match="BBB">
                <xsl:element name="BBB">
                        <xsl:attribute name="num">
                                <xsl:value-of select="//DDD/@id"></xsl:value-of>
                        </xsl:attribute>
                        <xsl:value-of select="."></xsl:value-of>
                </xsl:element>
        </xsl:template>
        
</xsl:stylesheet>

Thanks,
Michael


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