RE: use of xsl:key in cross-referencing

Dear Lars:

  Thank you for your reply, your solution is exactly
what I needed.  If creating a key with the same name
using two different groups that key off different
elements, then I need to use apply-templates
separately on the two different groups.  
  Also, you were right when you mention it will miss
QB instead of QC, must've been brain fart, argh!!

Thanks for the help, much appreciated.
Xiaocun

--- Lars Huttar <lars_huttar(_at_)sil(_dot_)org> wrote:

Dear Xiaocun,

To define two keys for the two groups with the

same

name but different "use":
<xsl:key name="QuestionnaireKey" match=//row[(_at_)row

&lt;

20]" use="string(cell[(_at_)column=2])"/>
<xsl:key name="QuestionnaireKey" match=//row[(_at_)row

&gt;

20]" use="string(cell[(_at_)column=1])"/>

Use Muenchian method to process each just once,

for

the 2nd group:
<xsl:apply-templates select="//row[(_at_)row &gt; 20

and

@row &lt; 30][count(.|key('QuestionnaireKey',
string(cell[(_at_)column=1]))[1]) = 1]"/>
but this will miss questionnaire QC.


Huh?  I can see how it will miss questionnaire QB,
but not QC.

I guess to take advantage of the combined key, I

need

to do select on all rows, like:
<xsl:apply-templates
select="//row[count(.|key('QuestionnaireKey',
string(cell[(_at_)column=1]))[1]) = 1]"/>
Would the above work?


I don't think so, because it uses @column=1 for all
rows,
instead of using @column=2 for the first group and
@column=1
for the second group.

If so, how can I tell if the
row being processed is from group 1

(Questionnaire) or

2 (Question)?


Above, you had "@row &gt; 20 and @row &lt; 30".  Do
you know
these boundary numbers in advance?  If so, why not
use them.

Here's a select expression and template that should
allow you to
process each Questionnaire once...

        <xsl:apply-templates
select="/range/row[count(.|key('QuestionnaireKey',
                                    
string(cell[(_at_)column=1 and
                                       ../@row &gt;
20] |
                                     cell[(_at_)column=2
and
                                       ../@row &lt;
20]))[1]) = 1]" />
...

  <xsl:template match="row">
    <p>
      <xsl:choose>
        <xsl:when test="@row &lt; 20">
          Processing Questionnaire <xsl:value-of
select="cell[(_at_)column=2]" />
        </xsl:when>
        <xsl:otherwise>
          Processing Questionnaire <xsl:value-of
select="cell[(_at_)column=1]" />
        </xsl:otherwise>
      </xsl:choose>
    </p>
  </xsl:template>

I tried this with your test data and it displayed 
      Processing Questionnaire QA
      Processing Questionnaire QB
      Processing Questionnaire QC

Does this solve your problem?

Lars



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