Re: use of xsl:key in cross-referencing

Hi, Wendell:

Thanks for the idea of define two keys for the two
groups with the same name but different "use" value,
but I was unable to find anything in regard to it at
Jenni's website, xsl-list archive (using keywords "two
key;same name;") or google web/group.  I did some
thinking myself and still don't see how that works. 
Following is an example, having rows 10-19 being the
first group (Questionnaire) and 20-29 being the second
group (Question):
<range>
<row row="16">
        <cell column="1">Questionnaire A</cell>
        <cell column="2">QA</cell>
        <cell column="3">Questionnaire A, two
questions</cell>
</row>
<row row="17">
        <cell column="1">Questionnaire B</cell>
        <cell column="2">QB</cell>
        <cell column="3">Questionnaire B, empty with no
questions</cell>
</row>

<row row="27">
        <cell column="1">QA</cell>
        <cell column="2">Questionnaire A, Question 1<cell>
</row>
<row row="28">
        <cell column="1">QA</cell>
        <cell column="2">Questionnaire A, Question 2</cell>
</row>
<row row="29">
        <cell column="1">QC</cell>
        <cell column="2">Questionnaire C, Question 1</cell>
</row>
</range>

In this case, questionnaire QA has two questions, QB
is only referred in the 1st group and QC is only
referred in the 2nd group.  What I need is to be able
to process each of QA/QB/QC.

To define two keys for the two groups with the same
name but different "use":
<xsl:key name="QuestionnaireKey" match=//row[(_at_)row &lt;
20]" use="string(cell[(_at_)column=2])"/>
<xsl:key name="QuestionnaireKey" match=//row[(_at_)row &gt;
20]" use="string(cell[(_at_)column=1])"/>

Use Muenchian method to process each just once, for
the 2nd group:
<xsl:apply-templates select="//row[(_at_)row &gt; 20 and
@row &lt; 30][count(.|key('QuestionnaireKey',
string(cell[(_at_)column=1]))[1]) = 1]"/>
but this will miss questionnaire QC.

I guess to take advantage of the combined key, I need
to do select on all rows, like:
<xsl:apply-templates
select="//row[count(.|key('QuestionnaireKey',
string(cell[(_at_)column=1]))[1]) = 1]"/>
Would the above work?  If so, how can I tell if the
row being processed is from group 1 (Questionnaire) or
2 (Question)?

Thanks,
Xiaocun

--- Wendell Piez <wapiez(_at_)mulberrytech(_dot_)com> wrote:
> Xiaocun,
>
> At 07:39 PM 3/19/2003, you wrote:
> > > >   When I process the 1st group of rows
> > > > (questionnaires), I call key() function by
> passing
> > > in
> > > > the value in the 2nd cell.
> > > Ignore the first group of rows and just iterate
> over
> > > the questions, using
> > > your key to group them.
> > That was the first came to my mind as well, but the
> > problem is that a questionnaire defined in 1st
> group
> > may not be used in the 2nd group, those will be
> > omitted.  I am looking for a way to combine the two
> > groups so that every questionnaire is processed as
> > long as it is used in 1st (questionnaires) or 2nd
> > group (questions). Order to me is not important.
> In that case, you can iterate over and de-duplicate
> from both groups.
>
> In fact, you can define two keys for the two groups
> with the same name, 
> only different "use" values, which could help in
> this.
>
> I'd be more explicit about this, except (a) it's
> much harder to write up 
> without some sample code to chew on (please post
> again with your source and 
> problem statement?), and (b) I'm in a time crunch
> today.
>
> But I learned this trick from Jeni: I think if you
> look in the FAQ and on 
> Jeni's site (http://www.jenitennison.com), where
> grouping is covered in 
> some detail, you could find something.
>
> Cheers,
> Wendell
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> Wendell Piez                           
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