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AW: Getting the value of the tag itself.

2003-03-20 08:30:27
<xsl:value-of select="name()"/> 

- Robin
                                                     
Robin Delaney
FJA Feilmeier & Junker GmbH    
Elsenheimerstraße 65,   80687 München.
*   +49 (0) 89 - 76 901-7058
Fax   +49 (0) 89 - 76 901-9502
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*    Mailto:Robin(_dot_)Delaney(_at_)fja(_dot_)com      




-----Ursprüngliche Nachricht-----
Von:  Simon Kelly [SMTP:kelly(_at_)ipe(_dot_)fzk(_dot_)de]
Gesendet am:  Donnerstag, 20. März 2003 16:08
An:   xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Betreff:      [xsl] Getting the value of the tag itself.

Hi all,

I know haow to get all the relevent information from a node, but I am
struggling to remeber how to get the nodes name itself.  IE if I have a
node
called <table name="table1"> how do I print out it's name table, and not
the
@name table1??

Cheers

Simon



Institut fuer
Prozessdatenverarbeitung
und Elektronik,
Forschungszentrum Karlsruhe GmbH,
Postfach 3640,
D-76021 Karlsruhe,
Germany.

Tel: (+49)/7247 82-4042
E-mail : kelly(_at_)ipe(_dot_)fzk(_dot_)de


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