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Re: Re: Re: dynamic XPath?

2003-03-12 23:09:21
We seem to agree on everything now.

Do we also agree that the following code does not produce the "Standard
expression to create a string for the path of the current node " ?

<!-- Standard expression to create a string for the path of the
current node --> <xsl:variable name='path'>
/<xsl:for-each select="ancestor::*">
   <xsl:value-of select="name()"
/>/</xsl:for-each><xsl:value-of select = "name()" />
</xsl:variable>



=====
Cheers,

Dimitre Novatchev.
http://fxsl.sourceforge.net/ -- the home of FXSL



"Passin, Tom" <tpassin(_at_)mitretek(_dot_)org> wrote in message
news:5D3C2276FD64424297729EB733ED1F7601D1BD1E(_at_)email1(_dot_)mitretek(_dot_)org(_dot_)(_dot_)(_dot_)
[Dimitre Novatchev]>
I think I may have misunderstood here, and perhaps you
misunderstood me
as well...  I understood the original question to ask for matching a
__string__ containing a path expression, like "/a/b/c"
(that is the kind
of example O thought that Yue Ma showed).  For my own post,
I put the
path string into a variable, thinking that it would
probably eventually
be sent in via a parameter.

Re-reading your comment, I notice that you might have
thought that I
was selecting a node set into the variable, instead of a string, but
that is not the case.

No, I also understand that the variable contains a string.

The problem of the expression (1):

/a/b/c

being generated for the node uniquly matched by (2):

/a/b[2]/c[3]

is that the former matches more than one node.


You can produce a string like (2) with a modification to the expression
I gave.  But ...

Whoever wants to identify a single node will not use (1) ,
but an expression
equivalent to (2).


Maybe, maybe not  - perhaps the original poster will tell us what he
really wants to do...

Cheers,

Tom P

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