If you know the maximum number of files you need to join together, you could
pass their names in through that number of parameters. E.G.
<xsl:param name="file-1" select="''"/>
<xsl:param name="file-2" select="''"/>
....
<xsl:if test="string-length($file-1) != 0" />
<xsl:value-of select="document($file-1)/XPath"/>
</xsl:if>
...
If you really have an unknown number of files to work on, then the approach
Jürgen suggests is probably the simplest and quickest.
Steve
-----Original Message-----
From: David Alcantara [mailto:wwwdavid(_at_)gmx(_dot_)de]
Sent: Wednesday, March 12, 2003 8:35 AM
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: AW: [xsl] 2 XML source
Thank you,
but it´s not so simple. :-(
every day i get approx. 100 XML files like 030312_01.xml (XML name =
date+position) and i want to have only one XSL :-)
Because every day other application creates 100's of xml files from which i
need to filter some data out of these files. As you said in your mail that
to incorporate the xml file names into the XSL File, i think in my case it
is difficult to type all the file names into the XSL File. So in this case I
request some other solution which suite my need given above.
maybe is easily make a C program who integreate the 100 xml files in other
one.
Is there a way to make C or C++ program.
Regards
david
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