Thank you,
but it´s not so simple. :-(
every day i get approx. 100 XML files like 030312_01.xml (XML name =
date+position) and i want to have only one XSL :-)
Because every day other application creates 100's of xml files from which i
need to filter some data out of these files. As you said in your mail that
to incorporate the xml file names into the XSL File, i think in my case it
is difficult to type all the file names into the XSL File. So in this case I
request some other solution which suite my need given above.
maybe is easily make a C program who integreate the 100 xml files in other
one.
Is there a way to make C or C++ program.
Regards
david
-----Ursprüngliche Nachricht-----
Von: owner-xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
[mailto:owner-xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com]Im Auftrag von
Jarkko
Moilanen
Gesendet: Mittwoch, 12. März 2003 12:40
An: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Betreff: Re: [xsl] 2 XML source
On Wed, 12 Mar 2003, David Alcantara wrote:
Hi,
i need to make a new XML file from 2 diferent XML source.
It´s possible?
Regards
david
I´m working with xalan 1.4.0
Yes it is and simple. =)
Use document() function.
For example:
<xsl:value-of select="document('source.xml')/XPath"/>
would look inside a file source.xml and traverse the tree
by the given XPath.
For more information see:
http://www.w3.org/TR/xslt#document
Cheers,
Jarkko.
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Researcher mutta todella suuret mokat
jm60697(_at_)uta(_dot_)fi vaativat tietokoneen käyttöä."
www.uta.fi/~jm60697
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